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0.08x^2+0.04x-375=0
a = 0.08; b = 0.04; c = -375;
Δ = b2-4ac
Δ = 0.042-4·0.08·(-375)
Δ = 120.0016
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.04)-\sqrt{120.0016}}{2*0.08}=\frac{-0.04-\sqrt{120.0016}}{0.16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.04)+\sqrt{120.0016}}{2*0.08}=\frac{-0.04+\sqrt{120.0016}}{0.16} $
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